Asked by James
A man lifts a 1.0 kg stone vertically with his hand at a constant upward acceleration of 1.8m/2^2. what is the magnitude of the total force of the stone on the man's hand?
In Newtons downward?
In Newtons downward?
Answers
Answered by
drwls
The man's hand pushes the stone upward with force F = m a + m g (since F - Mg is the net force)
The stone pushes the man's hand downward with the same force. (Because of Newton's third law)
The stone pushes the man's hand downward with the same force. (Because of Newton's third law)
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