Asked by confused

A 63.8 kg woman lifts herself 36.6 cm each time she does a chin-up. What force does she exert in lifting herself to the chin position?
And, how much positive work does she do in pulling herself up once?

Answers

Answered by Henry
a. F = m*g = 63.8 * 9.8 = 625.2 N.

b. Work = F*d = 625.2 * 0.366 = 228.8 J.


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