Asked by confused
A 63.8 kg woman lifts herself 36.6 cm each time she does a chin-up. What force does she exert in lifting herself to the chin position?
And, how much positive work does she do in pulling herself up once?
And, how much positive work does she do in pulling herself up once?
Answers
Answered by
Henry
a. F = m*g = 63.8 * 9.8 = 625.2 N.
b. Work = F*d = 625.2 * 0.366 = 228.8 J.
b. Work = F*d = 625.2 * 0.366 = 228.8 J.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.