Asked by Kate
A motor lifts a 70.0 kg box off the ground, starting from rest. In 8.00 seconds it lifts the box to a height of 20.0 m. At that time, the box is moving upward with a velocity of 5.00 m/s. What is the average power of the motor during this time interval?
Answers
Answered by
Elena
P =W/t = ΔE/t = (m•g•h +m•v²/2)/t
Answered by
aladesote T J
1820w
Answered by
Drake
P =W/t = ΔE/t = (m•g•h +m•v²/2)/t
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.