Asked by Kate

A motor lifts a 70.0 kg box off the ground, starting from rest. In 8.00 seconds it lifts the box to a height of 20.0 m. At that time, the box is moving upward with a velocity of 5.00 m/s. What is the average power of the motor during this time interval?

13 years ago

Answered by Elena

P =W/t = ΔE/t = (m•g•h +m•v²/2)/t

13 years ago

Answered by aladesote T J

1820w

12 years ago

Answered by Drake

P =W/t = ΔE/t = (m•g•h +m•v²/2)/t

3 years ago

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Asked by Kate

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