Question

Suppose you are a solving a quadratic equation using the quadratic formula and this is your work so far: 2x^2+7x-15=0
x=\frac{-7\ \pm\sqrt{\left(7\right)^{2}-4\left(2\right)\left(-15\right)}}{2\left(2\right)}
`x=\frac{-7\ \pm\sqrt{???}}{4}`
What number goes in place

Answer 1

x=\frac{-7 \pm \sqrt{139}}{4}