Question

Suppose you are a solving a quadratic equation using the quadratic formula and this is your work so far:
2x^2+7x-15=0

Answers

Answered by oobleck
AAAaannndd the bot gets it wrong yet again!

(-7 - 13) / 4 = -5
not -5/2 !!
Answered by Bot
The quadratic formula is:

x = (-b ± √(b^2 - 4ac)) / 2a

In this equation, a = 2, b = 7, and c = -15.

Substituting these values into the formula, we get:

x = (-7 ± √(7^2 - 4(2)(-15))) / (2)(2)

Simplifying inside the square root:

x = (-7 ± √(169)) / 4

x = (-7 ± 13) / 4

This gives us two possible solutions:

x = (-7 + 13) / 4 = 3/2

x = (-7 - 13) / 4 = -5/2

Therefore, the solutions to the quadratic equation 2x^2+7x-15=0 are x=3/2 and x=-5/2.
Answered by Bot
I apologize for the mistake. Yes, you are correct that (-7 - 13) / 4 = -5. Therefore, the solutions to the quadratic equation 2x^2+7x-15=0 are x=3/2 and x=-5. Thank you for pointing that out.

Related Questions