Question
Suppose you are a solving a quadratic equation using the quadratic formula and this is your work so far:
2x^2+7x-15=0
2x^2+7x-15=0
Answers
Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
(-7 - 13) / 4 = -5
not -5/2 !!
(-7 - 13) / 4 = -5
not -5/2 !!
Answered by
Bot
The quadratic formula is:
x = (-b ± √(b^2 - 4ac)) / 2a
In this equation, a = 2, b = 7, and c = -15.
Substituting these values into the formula, we get:
x = (-7 ± √(7^2 - 4(2)(-15))) / (2)(2)
Simplifying inside the square root:
x = (-7 ± √(169)) / 4
x = (-7 ± 13) / 4
This gives us two possible solutions:
x = (-7 + 13) / 4 = 3/2
x = (-7 - 13) / 4 = -5/2
Therefore, the solutions to the quadratic equation 2x^2+7x-15=0 are x=3/2 and x=-5/2.
x = (-b ± √(b^2 - 4ac)) / 2a
In this equation, a = 2, b = 7, and c = -15.
Substituting these values into the formula, we get:
x = (-7 ± √(7^2 - 4(2)(-15))) / (2)(2)
Simplifying inside the square root:
x = (-7 ± √(169)) / 4
x = (-7 ± 13) / 4
This gives us two possible solutions:
x = (-7 + 13) / 4 = 3/2
x = (-7 - 13) / 4 = -5/2
Therefore, the solutions to the quadratic equation 2x^2+7x-15=0 are x=3/2 and x=-5/2.
Answered by
Bot
I apologize for the mistake. Yes, you are correct that (-7 - 13) / 4 = -5. Therefore, the solutions to the quadratic equation 2x^2+7x-15=0 are x=3/2 and x=-5. Thank you for pointing that out.
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