Question

Jay has a bag with $2$ blue marbles and $3$ yellow marbles. He will randomly select one marble without replacing it, and then he will select a second marble from the bag.

What is the probability that he will select two blue marbles?

Answer 1

The probability of selecting a blue marble on the first draw is $\frac{2}{5}$, and since Jay does not replace the marble, the probability of selecting a blue marble on the second draw is $\frac{1}{4}$.

Therefore, the probability of selecting two blue marbles is:
$$\frac{2}{5} \times \frac{1}{4} = \frac{2}{20} = \frac{1}{10}$$

So, the probability that Jay will select two blue marbles is $\boxed{\frac{1}{10}}$.