3. At the donut shop 1/2 of their donuts have frosting. Of the donuts with frosting, 3/4 of them have sprinkles. How many donuts have both frosting and sprinkles?%0D%0A*%0D%0A1 point%0D%0A3/6%0D%0A3/8%0D%0A4/6%0D%0A2/8

Answer 1

Let's break down the information provided:

1. Let \( D \) be the total number of donuts at the shop.
2. According to the problem, \( \frac{1}{2} \) of the donuts have frosting. Therefore, the number of donuts with frosting is: \[ \frac{1}{2} D \]
3. Of the donuts with frosting, \( \frac{3}{4} \) have sprinkles. To find the number of donuts that have both frosting and sprinkles, we take \( \frac{3}{4} \) of the donuts with frosting: \[ \frac{3}{4} \times \frac{1}{2} D = \frac{3}{8} D \]

So, the number of donuts that have both frosting and sprinkles is \( \frac{3}{8} D \).

Since the answer choices do not specify \( D \) and it appears we need the fractional part independent of \( D \), we can state that:

\[ \text{The fraction of donuts with both frosting and sprinkles is } \frac{3}{8}. \]

Thus, the answer is:

3/8