`-2x\le3x+10`

Answer 1

To solve the inequality `-2x ≤ 3x + 10`, we can begin by isolating x on one side of the inequality.

Adding 2x to both sides of the inequality gives `0 ≤ 5x + 10`.

Next, we can subtract 10 from both sides: `-10 ≤ 5x`.

To solve for x, divide both sides by 5: `-2 ≤ x`.

Thus, the solution to the inequality `-2x ≤ 3x + 10` is `x ≥ -2`.