To solve the inequality \(-2x + 5 + x \leq 3x + 13\), we first combine like terms:
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Combine terms on the left side: \[ -2x + x + 5 \leq 3x + 13 \] This simplifies to: \[ -x + 5 \leq 3x + 13 \]
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Now, we will isolate \(x\). First, we can add \(x\) to both sides: \[ 5 \leq 4x + 13 \]
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Next, subtract \(13\) from both sides: \[ 5 - 13 \leq 4x \] This gives us: \[ -8 \leq 4x \]
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Now divide both sides by \(4\): \[ -\frac{8}{4} \leq x \] Which simplifies to: \[ -2 \leq x \] or equivalently: \[ x \geq -2 \]
The solution set for the inequality is \(x \geq -2\), which can be represented graphically as a number line where all numbers greater than or equal to \(-2\) are included.
In a graphing representation, this would look like a filled (or solid) point at \(-2\) with a line extending to the right towards positive infinity. Look for a graph that represents that.