To determine if a point is a solution for the simultaneous inequalities \(y > 6x - 4\) and \(y \le 3x + 2\), we need to check whether the point satisfies both inequalities.
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Identify the point: You would typically have a specific point (x, y) to test. But, since no specific coordinates are given, let's denote the point as \((x_0, y_0)\).
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Check the first inequality: For the point to satisfy \(y > 6x - 4\):
- Substitute \(y_0\) for \(y\) and \(x_0\) for \(x\): \[ y_0 > 6x_0 - 4 \]
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Check the second inequality: For the point to satisfy \(y \le 3x + 2\):
- Substitute \(y_0\) for \(y\) and \(x_0\) for \(x\): \[ y_0 \le 3x_0 + 2 \]
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Conclusion: If both conditions are true, the point is a solution; otherwise, it is not.
Since the actual point was not provided, I cannot compute a definitive answer. If you can provide the coordinates of the point, we can check these inequalities and provide a specific answer of 1 (yes) or 2 (no).
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