2H2S(g)---2H2(g) + S2 delta H=220KJ
k eq is 0.40
a 10.0L vessel containing 2.0 mol of H2S, 2.2 mol of H2, and 2.5 mol of S2
Calculate a trail k eq value to see whether the reaction is at equilibrium.
trail k eq =(h2)^2(S2)/(H2S)^2
= (0.22)^2(0.25)/(0.2)^2
= 0.3025 therefor keq < k eq
In which direction must the system move in order to reach equilibrium? why?
The equation must shift rigth because the numerator is not large enough. Since the numerator contains the product more product must be made in order to bring the ratio up to the value of 0.40
1 answer
right