Question
In the reaction 2H2S + 3O2 -> 2SO2 +2H2O, the oxidizing agent is
1.oxygen
2.water
3.sulfur dioxide
4.hydrogen sulfide
oxygen?
1.oxygen
2.water
3.sulfur dioxide
4.hydrogen sulfide
oxygen?
Answers
I agree.
Loss of electrons is oxidization.
Gain of e is reduction.
The substance oxidized is the reducing agent.
The substance reduced is the oxidization agent.
Therefore, oxidizing agent is reduced which means gain of e. O2 goes from zero to -2. That's a gain of electrons.
Loss of electrons is oxidization.
Gain of e is reduction.
The substance oxidized is the reducing agent.
The substance reduced is the oxidization agent.
Therefore, oxidizing agent is reduced which means gain of e. O2 goes from zero to -2. That's a gain of electrons.
water
sulfur dioxide
Which is reducing agent?
its oxygen
Related Questions
2H2S + 3O2 → 2H2O +2SO2 given the balanced equation, if 4 moles of hydrogen sulfide react:
How ma...
How many litres of oxygen are needed to react completely with 25.0L of H2S at STP according to the f...
In the reaction: 2H2S + 302 > 2502 + 2H20, the oxidizing agent is
A.oxygen
B.water
C.sulfur dio...
Is 2H2S(g) + O2(g)—> 2S(s) + 2H2O(l) a redox reaction? What is the reducing agent and what is the ox...