Asked by HELP! PLZ
2H2(g) + S2(g) ¡ê 2H2S(g)
Analysis of the contents of a 15.0L flask reveals that there are 4.4 moles of hydrogen gas, 2.0 moles of sulfur gas, and 3.7 moles of hydrogen sulfide gas in the flask at equilibrium. Calculate the equilibrium constant K
Analysis of the contents of a 15.0L flask reveals that there are 4.4 moles of hydrogen gas, 2.0 moles of sulfur gas, and 3.7 moles of hydrogen sulfide gas in the flask at equilibrium. Calculate the equilibrium constant K
Answers
Answered by
DrBob222
M each = mols/L = ?
Substitute M of each into the Keq expression for H2 + S2 ==> 2H2S and solve for Keq.
Substitute M of each into the Keq expression for H2 + S2 ==> 2H2S and solve for Keq.
Answered by
HELP! PLZ
i got an answer of 39.776 because i did [mol/L H2S]^2/ [mol/L H2]^2[mol/L S2]^2 so im not sure what went wrong
Answered by
DrBob222
What numbers did you substitute for concns H2, S2, H2S?
That should be (H2) = 4.4/15 = ?
(S2) = 2/15 = ?
(H2S) = 3.7/15 = ?
I suspect that's the problem.
That should be (H2) = 4.4/15 = ?
(S2) = 2/15 = ?
(H2S) = 3.7/15 = ?
I suspect that's the problem.
Answered by
HELP! PLZ
i used those exact numbers
Answered by
DrBob222
And your answers were?
Answered by
HELP! PLZ
after squaring i ended up with 0.060844444/ (1.529679004 *10^(-3)) = 39.7759555
Answered by
DrBob222
What numbers do you get for
4.4/15 = ?
2/15 = ?
3.7/15 = ?
4.4/15 = ?
2/15 = ?
3.7/15 = ?
Answered by
HELP! PLZ
4.4/15= 0.293333333
2/15= 0.133333333
3.7/15= 0.246666666
2/15= 0.133333333
3.7/15= 0.246666666
Answered by
DrBob222
So K = (0.24666)^2/(0.2933)(0.1333) =
Punch in the top numbers and divide by the bottom numbers WITHOUT copying any numbers; i.e., leave everything in the calculatord come up with an answer. I don't get 39.
Punch in the top numbers and divide by the bottom numbers WITHOUT copying any numbers; i.e., leave everything in the calculatord come up with an answer. I don't get 39.
Answered by
HELP! PLZ
why don't we square the bottom numbers to?
Answered by
DrBob222
I forgot the square on H2.
That should be
K = (0.24666)^2/(0.2933)(0.1333)^2
That should be
K = (0.24666)^2/(0.2933)(0.1333)^2
Answered by
HELP! PLZ
also I got 1.556 but LON CAPA is telling me that is incorrect
Answered by
HELP! PLZ
okay with the squared H2 it is 11.67414 but again LON CAPA is saying it is incorrect
Answered by
DrBob222
Sorry. I shouldn't have type the oops in the first place.
The reaction is
H2 + S2 ==> 2H2S
Kc = (H2S)^2/(H2)(S2)
Kc = (0.24666)^2/*0.29333)(0.1333)
You square the H2S because the coefficient is 2.
You raise (H2) and (S2) to the first place since the coefficient for both is 1.
The reaction is
H2 + S2 ==> 2H2S
Kc = (H2S)^2/(H2)(S2)
Kc = (0.24666)^2/*0.29333)(0.1333)
You square the H2S because the coefficient is 2.
You raise (H2) and (S2) to the first place since the coefficient for both is 1.
Answered by
HELP! PLZ
Doing that i get answer to be 1.56 but again it says incorrect
Answered by
HELP! PLZ
nevermind answer is 5.3 i had to square H2 which was (0.2933) and then multiply. Thank for everything Dr.Bob :)
Answered by
DrBob222
I typed the wrong equation in so I'm wrong too. Here is how it goes.
2H2 + S2 ==> 2H2S
Kc = (H2S)^2/(H2)^2(S2)
Kc = (0.24666)^2/(0.2933)^2(0.1333)
Kc = 5.3057
You have in the original problem, assuming you typed in all the digits, 4.4, 2.0 and 3.7 and 15.0.
That allows just two significant figures. So the answers should be rounded to 5.3. If the numbers were 4.40 and 2.00 and 3.70 let me know and the number of significant figures will change.
2H2 + S2 ==> 2H2S
Kc = (H2S)^2/(H2)^2(S2)
Kc = (0.24666)^2/(0.2933)^2(0.1333)
Kc = 5.3057
You have in the original problem, assuming you typed in all the digits, 4.4, 2.0 and 3.7 and 15.0.
That allows just two significant figures. So the answers should be rounded to 5.3. If the numbers were 4.40 and 2.00 and 3.70 let me know and the number of significant figures will change.
Answered by
DrBob222
I'm glad you understand it. I don't know when I've screwed a simple problem up so badly and it all goes back to writing the equation incorrectly. Let that be a lesson. Make sure the equations you work with are balanced.
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