2CH3OH(l)+3O2(g)-->2CO2(g)+4H20 +1350 kj

Question

1. What mass of water could be heated from 20.0 C to 35 C,by burning 48g of methanol?

This is what I did, no answer was given so I want to double check.
so q=mcT change in H=n(molar enthalpy)
c= 4.184 kj/(kg C)

So what I did was divide 1350 kj by 2 to get the molar enthalphy of methanol.
Than from the mass given I found the mols of methanol; about 1.5 mols. I than multipled 1.5 mols by 675 kj/mol. I found the enthalpy to be 1013 kj. Than using the quanity of heat equation Q=mcT I found the mass of water to be 16 kg.

Answer 1

I worked it separately and obtained 16.1 kg. I don't know how many zeros you have on 35 degrees and 48 g so watch the significant figures. You appear to have used the correct procedure.