2CH3OH(g)→2CH4(g)+O2(g)ΔH=+252.8kJ

Question

For a given sample of CH3OH, the enthalpy change during the reaction is 82.2kJ . How many grams of methane gas are produced?

Answer 1

Just treat the 82.2 kJ as a product of the reaction and use stoichiometry to found out how many moles of methane were used like so...

82.2kJ x 2mol CH4/252.8 kJ = ?

Then just multiply by the molar mass of methane (about 16.042g) to find how many grams of methane gas are produced from the reaction.

Answer 2

10.4 grams

Answer 3

Thank you!