Asked by Victoria
2CH3OH(l) + 3O2(g) → 2CO2(g) + 4H2O(l) ΔH° = -1199 kJ
How many kilojoules are liberated by the combustion of 56.4 g of methanol?
How many kilojoules are liberated by the combustion of 56.4 g of methanol?
Answers
Answered by
DrBob222
1199 kJ x (56.4g/2*molar mass CH3OH) = ?
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