The position vector of points A and B are 5i+4j-6k and 2i-2j respectively . A point x divides AB in the ratio (-3:5).find the coordinates of x

Answer 1

Let the coordinates of point x be (x1, x2, x3).

Using the section formula, we can find x1, x2, and x3.

x1 = (-3*2 + 5*5)/(5+3) = (10-15)/8 = -5/8
x2 = (-3*(-2) + 5*4)/(5+3) = (6+20)/8 = 26/8 = 13/4
x3 = (-3*(-6) + 5*0)/(5+3) = (18)/8 = 9/4

Therefore, the coordinates of point x are (-5/8, 13/4, 9/4).