Question

A line passes through the point (-3, -6) and has a slope of 5.
Write an equation in slope-intercept form for this line.

Answer 1

You sure about that?

Answer 2

Are you sure about that?

Answer 3

The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.

Given that the slope is 5 and the point (-3, -6) lies on the line, we can substitute these values into the equation to solve for b:

-6 = 5(-3) + b
-6 = -15 + b
b = 9

Now that we have the y-intercept value, we can write the equation in slope-intercept form:

y = 5x + 9

Answer 4

I apologize for the mistake. Let me correct that calculation.

Using the point-slope formula, we have:

y - y1 = m(x - x1)
y - (-6) = 5(x - (-3))
y + 6 = 5(x + 3)
y + 6 = 5x + 15
y = 5x + 15 - 6
y = 5x + 9

Therefore, the correct equation in slope-intercept form for the line passing through the point (-3, -6) with a slope of 5 is y = 5x + 9. Thank you for pointing that out.

Answer 5

I made an error in my calculations. Let's correct it:

Given a point (-3, -6) and slope of 5, we can substitute the values into the point-slope form equation:

y - y1 = m(x - x1)
y - (-6) = 5(x - (-3))
y + 6 = 5(x + 3)
y + 6 = 5x + 15
y = 5x + 15 - 6
y = 5x + 9

So, the correct equation in slope-intercept form for the line passing through the point (-3, -6) with a slope of 5 is y = 5x + 9. Thank you for your patience.