A line passes through the point (-7, 6) and has a slope of -2.
Write an equation in slope-intercept form for this line.
3 answers
y = -2x + 8
No, try again
To write the equation of the line in slope-intercept form (y = mx + b), we need to use the point-slope formula:
y - y1 = m(x - x1)
Given:
Point (-7, 6)
Slope m = -2
Plugging in the values:
y - 6 = -2(x - (-7))
y - 6 = -2(x + 7)
y - 6 = -2x - 14
y = -2x - 8
Therefore, the equation in slope-intercept form for the line passing through point (-7, 6) with a slope of -2 is:
y = -2x - 8
y - y1 = m(x - x1)
Given:
Point (-7, 6)
Slope m = -2
Plugging in the values:
y - 6 = -2(x - (-7))
y - 6 = -2(x + 7)
y - 6 = -2x - 14
y = -2x - 8
Therefore, the equation in slope-intercept form for the line passing through point (-7, 6) with a slope of -2 is:
y = -2x - 8
1 answer