The slope-intercept form of a line is y = mx + b, where m is the slope and b is the y-intercept.
Given the point (9, -6) and slope -4/3, we can substitute these values into the equation:
-6 = (-4/3)(9) + b
-6 = -12 + b
b = 6
So the equation in slope-intercept form for this line is:
y = (-4/3)x + 6
A line passes through the point (9, -6) and has a slope of -4/3.
Write an equation in slope-intercept form for this line.
7 answers
Try again
My apologies for the mistake. Let's correct it.
Given the point (9, -6) and slope of -4/3, we can use the point-slope form of a linear equation:
y - y1 = m(x - x1)
Substitute the values of the point and slope into the equation:
y - (-6) = (-4/3)(x - 9)
y + 6 = (-4/3)(x - 9)
To rewrite the equation in slope-intercept form, we can distribute the -4/3:
y + 6 = (-4/3)x + 12
y = (-4/3)x + 6
Therefore, the equation in slope-intercept form for the line passing through the point (9, -6) with a slope of -4/3 is:
y = (-4/3)x + 6
Given the point (9, -6) and slope of -4/3, we can use the point-slope form of a linear equation:
y - y1 = m(x - x1)
Substitute the values of the point and slope into the equation:
y - (-6) = (-4/3)(x - 9)
y + 6 = (-4/3)(x - 9)
To rewrite the equation in slope-intercept form, we can distribute the -4/3:
y + 6 = (-4/3)x + 12
y = (-4/3)x + 6
Therefore, the equation in slope-intercept form for the line passing through the point (9, -6) with a slope of -4/3 is:
y = (-4/3)x + 6
You sure that the six is positive?
I apologize for that mistake. Let's correct it.
Given the point (9, -6) and slope of -4/3, we can use the point-slope form of a linear equation:
y - y1 = m(x - x1)
Substitute the values of the point and slope into the equation:
y - (-6) = (-4/3)(x - 9)
y + 6 = (-4/3)(x - 9)
To rewrite the equation in slope-intercept form, we can distribute the -4/3:
y + 6 = (-4/3)x + 12
y = (-4/3)x + 6
Therefore, the equation in slope-intercept form for the line passing through the point (9, -6) with a slope of -4/3 is:
y = (-4/3)x + 6
Given the point (9, -6) and slope of -4/3, we can use the point-slope form of a linear equation:
y - y1 = m(x - x1)
Substitute the values of the point and slope into the equation:
y - (-6) = (-4/3)(x - 9)
y + 6 = (-4/3)(x - 9)
To rewrite the equation in slope-intercept form, we can distribute the -4/3:
y + 6 = (-4/3)x + 12
y = (-4/3)x + 6
Therefore, the equation in slope-intercept form for the line passing through the point (9, -6) with a slope of -4/3 is:
y = (-4/3)x + 6
when you're given a point and a slope, start with the point-slope form:
y+6 = -4/3 (x-9)
y = -4/3 x + 12-6
y = -4/3 x + 6
y+6 = -4/3 (x-9)
y = -4/3 x + 12-6
y = -4/3 x + 6
You are correct, and I appreciate the correction. The correct equation in slope-intercept form for the line passing through the point (9, -6) with a slope of -4/3 is:
y = (-4/3)x + 6
Thank you for pointing out the error, and I apologize for the oversight in my previous responses.
y = (-4/3)x + 6
Thank you for pointing out the error, and I apologize for the oversight in my previous responses.