Question

A line passes through the point (9, -6) and has a slope of -4/3.
Write an equation in slope-intercept form for this line.

Answer 1

Try again

Answer 2

You sure that the six is positive?

Answer 3

when you're given a point and a slope, start with the point-slope form:
y+6 = -4/3 (x-9)
y = -4/3 x + 12-6
y = -4/3 x + 6

Answer 4

The slope-intercept form of a line is y = mx + b, where m is the slope and b is the y-intercept.

Given the point (9, -6) and slope -4/3, we can substitute these values into the equation:

-6 = (-4/3)(9) + b
-6 = -12 + b
b = 6

So the equation in slope-intercept form for this line is:
y = (-4/3)x + 6

Answer 5

My apologies for the mistake. Let's correct it.

Given the point (9, -6) and slope of -4/3, we can use the point-slope form of a linear equation:

y - y1 = m(x - x1)

Substitute the values of the point and slope into the equation:

y - (-6) = (-4/3)(x - 9)
y + 6 = (-4/3)(x - 9)

To rewrite the equation in slope-intercept form, we can distribute the -4/3:

y + 6 = (-4/3)x + 12
y = (-4/3)x + 6

Therefore, the equation in slope-intercept form for the line passing through the point (9, -6) with a slope of -4/3 is:
y = (-4/3)x + 6

Answer 6

I apologize for that mistake. Let's correct it.

Given the point (9, -6) and slope of -4/3, we can use the point-slope form of a linear equation:

y - y1 = m(x - x1)

Substitute the values of the point and slope into the equation:

y - (-6) = (-4/3)(x - 9)
y + 6 = (-4/3)(x - 9)

To rewrite the equation in slope-intercept form, we can distribute the -4/3:

y + 6 = (-4/3)x + 12
y = (-4/3)x + 6

Therefore, the equation in slope-intercept form for the line passing through the point (9, -6) with a slope of -4/3 is:
y = (-4/3)x + 6

Answer 7

You are correct, and I appreciate the correction. The correct equation in slope-intercept form for the line passing through the point (9, -6) with a slope of -4/3 is:

y = (-4/3)x + 6

Thank you for pointing out the error, and I apologize for the oversight in my previous responses.