Question

A guitar string 60 cm in length, with a diameter of 1.4 mm and a tension of 289 N, emits a note with a frequence of 147 Hz. Find the frequency in each of the followig situations:

a)the tension isreduced to 196N
b)a string of the same material, 45 cm long and 1mm in diameter under 168 N of tension, is plucked.

a)I have no idea for a..
b)I was hoping someone could check my work on b?
=Fi(square root of tension fraction)(length fraction)(diameter fraction)
=147Hz(square root of 169/289)(60/45)(1.4/1)
=209.8Hz

I am just getting confused as to if the 289 goes on top of the fraction, or the 169.

thanks for your help in advance!
bobpursley
frequency new=frequency old *sqrt(169/289)

http://hyperphysics.phy-astr.gsu.edu/Hbase/waves/string.html
thanks Bob. Can you please help me with question A as well?

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