Asked by Anonymous
A fire helicopter carries a 640 kg bucket of water at the end of a 20.0 m long cable. Flying back from a fire at a constant speed of 40.0 m/s, the cable makes an angle of 42.0° with respect to the vertical. Determine the force exerted by air resistance on the bucket.
Answers
Answered by
drwls
Draw a free body diagram for the bucket.
The cable tension force is T
T cos 42 = bucket weight (which you know)
T sin 42 = air resistance force
Divide the second equation by the first. Remember that sin/cos = tan, for any angle.
tan 42 = (air resistance force)/weight
Solve for the unknown force
The cable tension force is T
T cos 42 = bucket weight (which you know)
T sin 42 = air resistance force
Divide the second equation by the first. Remember that sin/cos = tan, for any angle.
tan 42 = (air resistance force)/weight
Solve for the unknown force
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