Asked by Anonymous
From a fire tower, A, a fire is spotted on a bearing of N42°E. From a second tower, B, the fire is on a bearing of N12°W. The two fire towers are 23 km apart, and A is N63°W of B. How far is the fire from each tower?
Just need help interpreting the diagram from the question. Thank you in advanced.
Just need help interpreting the diagram from the question. Thank you in advanced.
Answers
Answered by
Reiny
My diagram has triangle ABF, with F as the fire.
angle A = 75°, angle B = 51° and angle F = 180-75-51 = 54°
also AB = 23 km
so you use the sine law to find the other two sides,
first one: AF/sin51 = 23/sin54
AF = 23sin51/sin54 = 22.09 km
find BF in a similar way.
angle A = 75°, angle B = 51° and angle F = 180-75-51 = 54°
also AB = 23 km
so you use the sine law to find the other two sides,
first one: AF/sin51 = 23/sin54
AF = 23sin51/sin54 = 22.09 km
find BF in a similar way.
Answered by
Anonymous
thanks so much!
Answered by
TIANHUANG
Why A=75°
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