Find the vertex of the function

Question

f(x) = 3x^2 - 6x + 4

Step by step moron

Answer 1

1. Find the x-coordinate of the vertex using the formula x = -b/2a, where a = 3 and b = -6 in the quadratic function f(x) = 3x^2 - 6x + 4.
x = -(-6)/(2*3)
x = 6/6
x = 1

2. Plug in the x-coordinate back into the function to find the y-coordinate of the vertex.
f(1) = 3(1)^2 - 6(1) + 4
f(1) = 3 - 6 + 4
f(1) = 1

Therefore, the vertex of the function f(x) = 3x^2 - 6x + 4 is (1, 1).