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Cole rewrote a quadratic function in vertex form. h(x)= x2−6x+7 Step 1: h(x)= (x2−6x+ 9 )+7 Step 2: h(x)=(x2−6x+ 9 )+7 −9 Step...Question
Felicia rewrote a quadratic function in vertex form.
h(x)= x^2−6x+7
Step 1: h(x)= (x^2−6x+ 9 )+7
Step 2: h(x)=(x^2−6x+ 9 )+7 −9
Step 3: h(x)=(x−3 )^2+2
Felicia said that the vertex is (3, 2). Is Felicia correct? If not, identify the step in which Felicia made the mistake and correct her work.
h(x)= x^2−6x+7
Step 1: h(x)= (x^2−6x+ 9 )+7
Step 2: h(x)=(x^2−6x+ 9 )+7 −9
Step 3: h(x)=(x−3 )^2+2
Felicia said that the vertex is (3, 2). Is Felicia correct? If not, identify the step in which Felicia made the mistake and correct her work.
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