Asked by Alex

April rewrote a quadratic function in vertex form.
h(x)=5^2-30x+30
step 1 h(x)=5(x^2-6x+ )+30
step 2 h(x)=5(x^2-6x+9)+30-45
step 3 h(x)= 5(x-3)^2+15
In which step did they make a mistake? and how? Please help

Answers

Answered by Reiny
I see two errors
1. should be h(x)=5x^2-30x+30 and not h(x)=5^2-30x+30
2. in step 2 to step 3, +30-45 = -15 , not +15
Answered by R_scott
you left the 1st x out of the original equation ... transcription mistake

but the error is in the last step ... the 15 should be negative
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