Asked by Anonymous
0.000014 mol of argon gas is placed in a 600 mL light bulb. What's the pressure of the gas in the bulb at 23C?
PV=nRT
(0.6L) X = (0.000014 mol) (0.08206 L-atm/mol-K)(296.15 K)
X= 5.7 *10^-4 atm ?
PV=nRT
(0.6L) X = (0.000014 mol) (0.08206 L-atm/mol-K)(296.15 K)
X= 5.7 *10^-4 atm ?
Answers
Answered by
DrBob222
Depending upon the 600 number (is that 600. or 6 x 10^2)-----
If 600. then the answer is 5.67 x 10^-4 atm. If 6 x 10^2, then the answer is 6 x 10^-4.
If 600. then the answer is 5.67 x 10^-4 atm. If 6 x 10^2, then the answer is 6 x 10^-4.
Answered by
Bun
Yes
Answered by
Anonymous
I don't understand... 600 is the same as 6*10^2.
"600 mL" was the original volume given in the question.
"600 mL" was the original volume given in the question.
Answered by
DrBob222
No, 6 x 10^2 has one significant figure, the 6, while 600. has 3 s.f. (Technically, 600 has only one since we don't know that the two zeros are significant. Placing the decimal after the second zero lets us know that 600 has three s.f.) To avoid confusion, we write 600. to mean three s.f. and we write 6 x 10^2 to mean 1 s.f.