Question
If 1.00mol of argon is placed in a 0.500- container at 28.0 degree Celsius, what is the difference between the ideal pressure (as predicted by the ideal gas law) and the real pressure (as predicted by the van der Waals equation)?
For argon,a=1.345(L square. atm)/mol square and b=0.03219L/mol .
For argon,a=1.345(L square. atm)/mol square and b=0.03219L/mol .
Answers
You know the ideal PV = nRT equation, and you know van der Waals equation. Plug and chug.
Related Questions
What volume of 15 degree celsius water must be added to a 1.2KG piece of stainless steel at 85 degre...
a copper container of mass 80g contains 60g of a liquid at 20 degree Celsius. a piece of copper of m...
A 1.30-L sample of argon gas is at 1.02 atm and 21.5 degrees Celsius. a. what mass of argon is in th...