Question

Container A contains argon gas at 0C and pressure 380mmHg. Container B of volume 700 ml contains neon gas at 25C and pressure of 3atm. Both of these gases are placed in a 2L vessel at 273K and the total pressure is 1.46atm. What is the volume of container A?
PV = nRT; solve for n = number mols Ar + Ne in the 2L vessel at the conditions listed.

PV = nRT in container B; solve for n = number of mols Ne.

Subtract total mols - mols Ne to give you mols Ar.

Then PV = nRT in container A; You have P, n, R, T; solve for V at the conditions listed.

Related Questions

Consider a 790-mL container at 21 °C in which the pressure of argon is 1.98x106 Pa. a) What mass... sealed metal container can withstand a pressure difference of 0.630 . The container initially is fil... A 355.0 ml container holds 0.146 g nitrogen gas and an unknown amount of argon at 35 degrees and a t... A mixture consists of 45% oxygen, 12% argon, and 43% nitrogen by volume. A sample of this mixture ha...