Asked by erika

A sample of argon at 300.°C and 50.0 atm pressure is cooled in the same container to a temperature of 0.°C. What is the new pressure?

Answers

Answered by DrBob222
(P1V1/T1)=(P2V2/T2)
Don't forget to change T to Kelvin.
V1=V2 and isn't needed in the equation.
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