Asked by Anonymous

A 813. mL sample of argon gas at 452. K is cooled at constant pressure until the volume becomes 356. mL. What is the new gas temperature in Kelvin?
Answered by Pre-med student
PV=PV
.813L*452=.356X
Answered by DrBob222
There is no P listed and the formula is not PV = PV. However the answer is correct.
It is (V1/T1) = (V2/T2)
(813/452) = (356/T2)
T2 = 813*452/356
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