A jeepney from rest

Question

accelerates uniformly over a time of 3.25 seconds and covers a distance of 15
meters. What will be the final velocity of the jeepney after 3.25 seconds?

Answer 1

To determine the final velocity of the jeepney after 3.25 seconds, we can use the equation:

v = u + at

Where:
v = final velocity
u = initial velocity (assuming the jeepney starts from rest, u = 0 m/s)
a = acceleration
t = time

Given that the jeepney accelerates uniformly and starts from rest (u = 0 m/s), the equation simplifies to:

v = at

We are given that the acceleration of the jeepney is constant and equal to the average acceleration over the time interval, so we can calculate the acceleration:

a = (final velocity - initial velocity) / time
a = (v - 0) / 3.25
a = v / 3.25

Given that the distance covered is 15 meters, we can use the equation for uniformly accelerated motion:

s = ut + (1/2)at^2

Plugging in the values we have:

15 = 0 + (1/2) * a * (3.25)^2
15 = (1/2) * a * 10.5625
15 = 5.28125a
a = 15 / 5.28125
a = 2.842 m/s^2

Now we can find the final velocity:

v = a * t
v = 2.842 * 3.25
v = 9.2385 m/s

Therefore, the final velocity of the jeepney after 3.25 seconds is approximately 9.24 m/s.