Ask a New Question

Question

a jeepney from rest accelerates unit fromly covers the time 3.25s. and covers in 15m.

Determine the acxeleration of jeepney
10 years ago

Answers

bobpursley
a= changevelocty/time=2(15/3.25)/3.25

10 years ago
jefferson
a=~2.84 m/s^2
9 years ago

Related Questions

If a car accelerates from rest at a constant 5.5m/s^2, how long will be required to reach 28m/s? a car accelerates from rest at a constant rate 'a' for some time. after which it decelerates at a co... A car accelerates from rest at a constant rate of 2.2 m/s2 for 6.9 s. How far does the car travel in... if a car accelerates from rest at a constant 5.5 m/s^2, how long will it take for the car to reach a... A car accelerates from rest at 2.57 m/s2. What is the velocity at the end of 5.4 s? Answer in unit... a car accelerates from rest to 28 m/s in 6 seconds. if the cars mass is 150.00 kg. what force is pr... A jeepney from rest accelerates uniformly over a time of 3.25 seconds and covers a distance of 15... A jeepney from rest accelerates uniformly over a time of 3.25 seconds and covers a distance of 15... A jeepney from rest accelerates uniformly over a time of 3.25 seconds and covers a distance of 15...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use