Question

A jeepney from rest
accelerates uniformly over a time of 3.25 seconds and covers a distance of 15
meters. What is the given initial velocity?

Answer 1

To find the initial velocity of the jeepney, we can use the formula for uniformly accelerated motion:

distance = (initial velocity * time) + (0.5 * acceleration * time^2)

Since the jeepney starts from rest, its initial velocity is 0 m/s. Therefore, the formula simplifies to:

distance = 0.5 * acceleration * time^2

Plugging in the given values:

15 meters = 0.5 * acceleration * (3.25 seconds)^2

Solving for acceleration:

acceleration = (15 meters) / (0.5 * (3.25 seconds)^2)
acceleration ≈ 2.77 m/s^2

We can now calculate the initial velocity using the formula:

initial velocity = (distance - 0.5 * acceleration * time^2) / time
initial velocity = (15 meters - 0.5 * 2.77 m/s^2 * (3.25 seconds)^2) / 3.25 seconds
initial velocity ≈ 1.89 m/s

Therefore, the given initial velocity of the jeepney is approximately 1.89 m/s.