Given that the picture produced at a distance of 20 ft has an area of 100 square feet, we can use the concept of similar triangles to find the area of the picture when the projection unit is moved to a distance of 30 ft.
When the projection unit is moved to a distance of 30 ft, the ratio of the distances is 30/20 = 3/2. This means that the dimensions of the picture will also have a ratio of 3/2.
Since area is proportional to the square of the dimensions, the area of the picture when the projection unit is moved to a distance of 30 ft will be:
(3/2)^2 * 100 sq ft = 9/4 * 100 sq ft = 225 square feet
Therefore, the area of the picture when the projection unit is moved to a distance of 30 ft will be 225 square feet.
a) If a 20-ft distance produces a 100 f picture, what is the area of the picture when the projection unit is moved to a distance of 30 ft
1 answer
1 answer