If a 16-ft distance produces a 64 ft picture, what is the area of the picture when the projection unit is moved to a distance of 20 ft from the wall?

Answer 1

To solve this problem, we can set up a proportion based on the relationship between the distance to the wall and the size of the picture.

Let x be the unknown area of the picture when the projection unit is moved to a distance of 20 ft from the wall.

Using the given information, we can set up the following proportion:

16 ft / 64 ft = 20 ft / x

Cross multiplying, we get:

16 * x = 64 * 20
16x = 1280
x = 1280 / 16
x = 80

Therefore, the area of the picture when the projection unit is moved to a distance of 20 ft from the wall is 80 square feet.