To find the area of the picture at a 20-ft distance, we need to use the concept of similar triangles. The ratio of the distances is 20 ft / 8 ft = 2.5. This means that the dimensions of the picture will also be enlarged by a factor of 2.5.
If the original picture had an area of 64 ft², then the area of the enlarged picture at a 20-ft distance would be:
Area = 64 ft² * (2.5)²
Area = 64 ft² * 6.25
Area = 400 ft²
Therefore, the area of the picture when the projection unit is moved to a distance of 20 ft from the wall would be 400 ft².
(a) If a 8-ft distance produces a 64 fỉ picture, what is the area of the picture when the projection unit is moved to a distance of 20 ft from the wall?
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