Question

Solve for x:
2log(3-x) = log2 + log(22-2x)

Answer 1

2log(3-x) = log2 + log(22-2x)
log(3-x)^2 - log(22-2x) = log2
log[(3-x)^2/(22-2x)] = log2

(3-x)^2/(22-2x) = 2
(3-x)^2 = 2(22-2x)

expand, express and solve as a quadratic, make sure x < 3