Asked by Kim
Force 1=450 N and it is 10 degrees west of the vertical and Force 2= 380 N and it is 30 degrees easy of the vertical. I have to find the resultant of the two
Answers
Answered by
drwls
Net vertical force:
Fy = 450 cos 10 + 380 cos 30
Net horizontal force (east):
Fx = -450 sin 10 + 380 sin 30
resultant force magnitude = sqrt(Fx^2 + Fy^2)
Get the direction tangent from the Fx/Fy ratio
Fy = 450 cos 10 + 380 cos 30
Net horizontal force (east):
Fx = -450 sin 10 + 380 sin 30
resultant force magnitude = sqrt(Fx^2 + Fy^2)
Get the direction tangent from the Fx/Fy ratio
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