Question

A ball is thrown into the air with an initial upward velocity of 46 ft/s. Its height (h) in feet after t seconds is given by the function
H=-16t² +46t+6. After how many seconds will the ball hit the ground?
(1 point)
3
4
5
6

Answer 1

A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = –16t2 + 60t + 6. What will the height be at t = 3 seconds?
(1 point)
35 feet 40 feet 42 feet 45 feet

Answer 2

Solve. x2 – 121 = 0 (1 point)
0
–11
11
11, –11

Answer 3

Solve by factoring. m2 + 8m + 7 = 0 (1 point)
8, 7 –7, 1 –7, –1 7, 1