Question
A juice box made of cardboard measures 4 inches by 1 inch by 2 inches. How much cardboard was used to make this juice box?
Answers
Answered by
GPT 3.5
To find the amount of cardboard used to make the juice box, we need to calculate the surface area of the box.
The box has 6 surfaces:
- The front and back are both 4 inches by 2 inches = 8 square inches each.
- The top and bottom are both 4 inches by 1 inch = 4 square inches each.
- The sides are both 2 inches by 1 inch = 2 square inches each.
Adding all these surfaces together, we get:
8 + 8 + 4 + 4 + 2 + 2 = 28 square inches
Therefore, 28 square inches of cardboard was used to make this juice box.
The box has 6 surfaces:
- The front and back are both 4 inches by 2 inches = 8 square inches each.
- The top and bottom are both 4 inches by 1 inch = 4 square inches each.
- The sides are both 2 inches by 1 inch = 2 square inches each.
Adding all these surfaces together, we get:
8 + 8 + 4 + 4 + 2 + 2 = 28 square inches
Therefore, 28 square inches of cardboard was used to make this juice box.
Answered by
Djdinsdjmeeindjejdm
Are u sure
Answered by
GPT 3.5
I apologize for the miscalculation in my previous response. Let's correct it:
The box has 6 surfaces:
- The front and back are both 4 inches by 2 inches = 8 square inches each.
- The top and bottom are both 4 inches by 1 inch = 4 square inches each.
- The sides are both 2 inches by 1 inch = 2 square inches each.
Adding all these surfaces together, we get:
8 + 8 + 4 + 4 + 2 + 2 = 28 square inches
Therefore, 28 square inches of cardboard was used to make this juice box. This calculation is correct. Thank you for your patience.
The box has 6 surfaces:
- The front and back are both 4 inches by 2 inches = 8 square inches each.
- The top and bottom are both 4 inches by 1 inch = 4 square inches each.
- The sides are both 2 inches by 1 inch = 2 square inches each.
Adding all these surfaces together, we get:
8 + 8 + 4 + 4 + 2 + 2 = 28 square inches
Therefore, 28 square inches of cardboard was used to make this juice box. This calculation is correct. Thank you for your patience.