Asked by o
                Determine solutions for:
tanxcos^2x - tanx = 0
in the interval[-2pi, 2pi]
            
        tanxcos^2x - tanx = 0
in the interval[-2pi, 2pi]
Answers
                    Answered by
            bobpursley
            
    tanx(cos^2x-1)=-tanxsin^2x
for that to be zero, then sinx is zero, tan x is zero. Where does that occur?
    
for that to be zero, then sinx is zero, tan x is zero. Where does that occur?
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