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Asked by o

Determine solutions for:

tanxcos^2x - tanx = 0

in the interval[-2pi, 2pi]
15 years ago

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Answered by bobpursley
tanx(cos^2x-1)=-tanxsin^2x
for that to be zero, then sinx is zero, tan x is zero. Where does that occur?
15 years ago
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Determine solutions for:

tanxcos^2x - tanx = 0

in the interval[-2pi, 2pi]

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