Asked by Anonymous
determine the solutions for tanxcos^2x-tanx=0 in the interval XE[-2pi,2pi]
Ok, please describe the steps to me that you used to solve this! thank you
Ok, please describe the steps to me that you used to solve this! thank you
Answers
Answered by
Reiny
tanx(cos^2 x - 1) = 0
tanx = 0 or cosx = ± 1
looking at tangents curves from -2pi to +2pi
x = -2pi , -pi, 0, pi, 2pi
looking at a cos curve where it is ±1
is -2pi, -pi 0, pi, and 2pi
so both parts had the same solutions,
x = 0, ±pi, ±2pi
tanx = 0 or cosx = ± 1
looking at tangents curves from -2pi to +2pi
x = -2pi , -pi, 0, pi, 2pi
looking at a cos curve where it is ±1
is -2pi, -pi 0, pi, and 2pi
so both parts had the same solutions,
x = 0, ±pi, ±2pi