Asked by Zu

Determine exact solutions for each equation in the interval x ∈ [0, 2π].
sinx + sqrt3 / 2 = 0
Answered by Anonymous
sin(x) - sqrt(3)/2 = 0
sin(x) = -sqrt(3)/2
x = -pi/3 + 2*pi*n AND -2pi/3 + 2*pi*n
= 5pi/3, 4pi/3

Have a nice day!
Answered by Zu
Why -2pi/3 + 2pi?
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