Calculate the surface area of the square pyramid that has a base length of 12 and a slant height of 18. Show your work. ANSWER LIKE A 7TH GRADER

Answer 1

To find the surface area of the square pyramid, we need to add the area of the base and the area of the four triangular faces.

First, let's find the area of the base:
Area of the base = side length x side length
Area of the base = 12 x 12
Area of the base = 144 square units

Next, let's find the area of one triangle:
The base of the triangle is the side length of the base of the pyramid, which is 12.
The height of the triangle can be found using the Pythagorean theorem:
height^2 + 6^2 = 18^2
height^2 + 36 = 324
height^2 = 288
height = sqrt(288)
height ≈ 16.97

Area of one triangle = 0.5 x base x height
Area of one triangle = 0.5 x 12 x 16.97
Area of one triangle ≈ 101.82 square units

Now, let's find the total surface area:
Total surface area = base area + 4 x triangle area
Total surface area = 144 + 4 x 101.82
Total surface area = 144 + 407.28
Total surface area ≈ 551.28 square units

Therefore, the surface area of the square pyramid is approximately 551.28 square units.

Answer 2

Simplify a bit more

Answer 3

Okay! The surface area of the square pyramid with a base length of 12 and a slant height of 18 is approximately 551.28 square units.

Answer 4

But still show the work but make it rlly ahort

Answer 5

Base area = 12 x 12 = 144 square units
Triangle area = 0.5 x 12 x 16.97 ≈ 101.82 square units
Total surface area = 144 + 4 x 101.82 ≈ 551.28 square units

Answer 6

Thanks <3

Answer 7

You're welcome! If you have any more questions, feel free to ask! <3