Asked by Anonymous
calculate the surface area of a sphere of which the volume is 9000mm^3
Answers
Answered by
Steve
v = 4/3 πr^3
r = ∛(3v/(4π))
a = 4πr^2 = 4π * (3v/(4π))^(2/3)
= ∛(36πv^2)
so, for your sphere,
a = ∛(36π*9000^2) = 900∛(4π) ≈ 2092
r = ∛(3v/(4π))
a = 4πr^2 = 4π * (3v/(4π))^(2/3)
= ∛(36πv^2)
so, for your sphere,
a = ∛(36π*9000^2) = 900∛(4π) ≈ 2092
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