First, we need to write a balanced chemical equation for the reaction:
HCl + NaOH -> NaCl + H2O
Next, we need to determine the limiting reactant.
1. Calculate the number of moles of each reactant:
- Moles of HCl = 29.5 g / 36.46 g/mol = 0.808 mol
- Moles of NaOH = 58.0 g / 40.00 g/mol = 1.45 mol
2. Determine the mole ratio of the reactants:
- From the balanced equation, the mole ratio of HCl to NaOH is 1:1.
3. Since the mole ratio is 1:1, HCl is the limiting reactant because it produces fewer moles of product.
4. Calculate the theoretical yield of water using the moles of the limiting reactant:
- 0.808 mol HCl * 1 mol H2O / 1 mol HCl = 0.808 mol H2O
5. Convert the moles of water to grams:
- 0.808 mol H2O * 18.015 g/mol = 14.6 g H2O
Therefore, the theoretical yield of water formed from the reaction of 29.5 g of hydrochloric acid and 58.0 g of sodium hydroxide is 14.6 g.