Asked by Brittany
                If you have Hydrochloric acid, how many grams of aluminum must you use to produce 57.0 L of hydrogen at STP?
2Al(s)+6HCl(aq) --> 3H2(g)+2AlCl3(aq)
            
        2Al(s)+6HCl(aq) --> 3H2(g)+2AlCl3(aq)
Answers
                    Answered by
            DrBob222
            
    Just follow the steps in this example.
http://www.jiskha.com/science/chemistry/stoichiometry.html
    
http://www.jiskha.com/science/chemistry/stoichiometry.html
                    Answered by
            Brittany
            
    I ended up getting 42.718333 not rounded to sig figs but does the excess of hydrochloric acid have anything to do with the answer and what about the STP?
    
                    Answered by
            DrBob222
            
    I have something like 45. something and the problem says nothing about excess HCl; however, it won't work this way unless HCl IS IN excess.
You use the 57.0 L at STP to calculate moles H2. Remember that 1 mole of a gas at STP occupies 22.4 L; therefore, 57.0/22.4 = ?? moles H2.
Then ?? moles H2 x (2 moles Al/3 moles H2) = ?? moles H2 x (2/3) = moles Al and that times molar mass Al = about 45 g or so Al.
    
You use the 57.0 L at STP to calculate moles H2. Remember that 1 mole of a gas at STP occupies 22.4 L; therefore, 57.0/22.4 = ?? moles H2.
Then ?? moles H2 x (2 moles Al/3 moles H2) = ?? moles H2 x (2/3) = moles Al and that times molar mass Al = about 45 g or so Al.
                    Answered by
            i3WclOmPHwQ
            
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