Asked by wallace
A 10 ml of hydrochloric acid solution of concentration equal to 0.1 mol per litre is added 90 ml of pure water. What's the pH of the final solution?
Answers
Answered by
DrBob222
Assuming the volumes are additive, the final concn of the HCl is
0.1 x (10/100) = 0.01 M so pH = = log(H^+). The H^+ contributed by the H2O is small enough to be ignored in this case.
0.1 x (10/100) = 0.01 M so pH = = log(H^+). The H^+ contributed by the H2O is small enough to be ignored in this case.
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