Asked by Steven
I have having difficulty understanding where L comes from in term symbol notation
For Carbon, e- configuration is 1s^2 2s^2 2p^2
p corresponds to l=1
overall spin is 3/2
since cell is less than half-full, J=S=3/2
so term symbol is 4 P (3/2)
this i understand where P came from
---------------------------
But for Nb2+ where it is 4d^3
It is 3 F (4)
Isn't d corresponding to l=2
so shouldn't it be 3 D (4)?
For Carbon, e- configuration is 1s^2 2s^2 2p^2
p corresponds to l=1
overall spin is 3/2
since cell is less than half-full, J=S=3/2
so term symbol is 4 P (3/2)
this i understand where P came from
---------------------------
But for Nb2+ where it is 4d^3
It is 3 F (4)
Isn't d corresponding to l=2
so shouldn't it be 3 D (4)?
Answers
Answered by
DrBob222
Isn't the ground state of carbon <sup>3</sup>P<sub>o</sub>
Answered by
Steven
You are correct DrBob. Error on my part.
Answered by
Steven
But for Nb2+ where it is 4d^3
Shouldn't L be D instead of F?
Like p^2 in carbon, L = P
And in s^2, L = S
------
Or am I going about this the wrong way?
Shouldn't L be D instead of F?
Like p^2 in carbon, L = P
And in s^2, L = S
------
Or am I going about this the wrong way?
Answered by
DrBob222
No, L = 3.
You have 3d electrons, they occupy M<sub>l</sub> =
+2---+1---0
Add 2 + 1 + 0 = 3 which is F.
When you had 4d4 5s1 (in the neutral Nb) it is figured as
+2--+1--+0-- -1 --
So you add +2+1+0-1 for the d electrons and 0 for the s electron and the total is 2 which is D.
You have 3d electrons, they occupy M<sub>l</sub> =
+2---+1---0
Add 2 + 1 + 0 = 3 which is F.
When you had 4d4 5s1 (in the neutral Nb) it is figured as
+2--+1--+0-- -1 --
So you add +2+1+0-1 for the d electrons and 0 for the s electron and the total is 2 which is D.
Answered by
Steven
what about Nb2+ then?
it has 8 electrons
it occupies 2, 1, 0, -1, -2
so would that make L = 0 which is S?
it has 8 electrons
it occupies 2, 1, 0, -1, -2
so would that make L = 0 which is S?
Answered by
DrBob222
Have you confused yourself?
Your earlier post said Nb^+2 was 4d3 and that is correct. So where do you get this 4d8 stuff?
If Nb is 4d4 5s1, then remove the 5s and 1 of the 4d to make Nb^+2 and that leaves Nb^+2 = 4d3 for which
2 + 1 + 0 = 3 and that is F.
Your earlier post said Nb^+2 was 4d3 and that is correct. So where do you get this 4d8 stuff?
If Nb is 4d4 5s1, then remove the 5s and 1 of the 4d to make Nb^+2 and that leaves Nb^+2 = 4d3 for which
2 + 1 + 0 = 3 and that is F.
Answered by
Steven
Thank you Dr Bob. Yes, I am seriously confusing myself haha
As far as the 4d8 is concerned, I was referring to Ni2+
it has 8 electrons
it occupies 2, 1, 0, -1, -2
so would that make L = 0 which is S?
Sorry for the confusion. I greatly appreciate you staying and helping me despite my many errors.
As far as the 4d8 is concerned, I was referring to Ni2+
it has 8 electrons
it occupies 2, 1, 0, -1, -2
so would that make L = 0 which is S?
Sorry for the confusion. I greatly appreciate you staying and helping me despite my many errors.
Answered by
Steven
OHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH.
if it was 8e- in d orbitals (5 of em)
it would be +2 +1 0 -1 -2 for up spin , then +2 +1 and 0 for down spin!
therefore, total is 3 and L=3!!!!
I hope this is correct!
if it was 8e- in d orbitals (5 of em)
it would be +2 +1 0 -1 -2 for up spin , then +2 +1 and 0 for down spin!
therefore, total is 3 and L=3!!!!
I hope this is correct!
Answered by
DrBob222
Your OHHHHH is right on. L = 3
There are two unpaired electrons; therefore, s = 1/2 + 1/2 = 1 and M = 2S + 1 = 3
L = 3
and since the d shell is more than half filled, J = L + S = 3 + 1 = 4 so
<sup>3</sup>F<sub>4</sub> is the term symbol. By the way, you can check any element by going to www.webelements.com, clicking on the element, scrolling down and slicking on electronic properties, then scrolling down to see the electronic configuration and the term symbol.
Here is the Ni^+2 (but Ni neutral element) is the same.
There are two unpaired electrons; therefore, s = 1/2 + 1/2 = 1 and M = 2S + 1 = 3
L = 3
and since the d shell is more than half filled, J = L + S = 3 + 1 = 4 so
<sup>3</sup>F<sub>4</sub> is the term symbol. By the way, you can check any element by going to www.webelements.com, clicking on the element, scrolling down and slicking on electronic properties, then scrolling down to see the electronic configuration and the term symbol.
Here is the Ni^+2 (but Ni neutral element) is the same.
Answered by
Steven
Dr Bob,
Thank you so much!! You have taught me something in mere minutes that my professor failed to do in a single lecture. And thank you again for the web site. I had no idea such a site existed!
I wish there was a karma/rep system :)
thanks again
Thank you so much!! You have taught me something in mere minutes that my professor failed to do in a single lecture. And thank you again for the web site. I had no idea such a site existed!
I wish there was a karma/rep system :)
thanks again
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